RSP’s Amarkanta Chaudhary defeats Upendra Yadav in Saptari-3

Chaudhary secures 32,875 votes, beating the JSP-N chair by over 17,000 votes. RSP’s Amarkanta Chaudhary defeats Upendra Yadav in Saptari-3

Published at : March 8, 2026

Updated at : March 8, 2026 11:19

Saptari

Amarkanta Chaudhary of the Rastriya Swatantra Party has been elected from Saptari-3 in the House of Representatives elections.

Chaudhary defeated Janata Samajbadi Party-Nepal chair Upendra Yadav by a margin of more than 17,000 votes.

Chaudhary secured 32,875 votes, while Yadav received 15,239 votes.

Dinesh Kumar Gupta of Nepali Congress obtained 8,424 votes, and Tarakanta Chaudhary of CPN-UML received 6,715 votes.

Without Fear or FavourUNWIND IN STYLE